The value of x in mx + ny = c; nx - ny = c + 1 is
x = (2c + 1) / (m + n)
x = m + n
x = (m + n) / (c + 1)
x = 2c + 1
mx + ny = c.............(1)
nx - ny = c + 1.........(2) add the eqs (1) & (2).
(m + n) x = 2c + 1
If y=[x+√x2+a2]n,then dydx is equal to