wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The vectors a^i+2a^j3a^k, (2a+1)^i+(2a+3)^j+(a+1)^k and (3a+5)^i+(a+5)^j+(a+2)^k are non-coplanar for the range of a in

A
{0}
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
(0,)
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
(,1)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
(1,)
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct options are
B (0,)
D (1,)
∣ ∣a2a3a2a+12a+3a+13a+5a+5a+2∣ ∣\
Taking a common from R1, we get
=a∣ ∣1232a+12a+3a+13a+5a+5a+2∣ ∣
Applying R2R2(2a+1)R1;R3R3(3a+5)R1, we get
=a∣ ∣12302a+17a+405(a+1)10a+17∣ ∣=a(15a2+31a+37)0 for a0
Hence three vectors are coplanar only for a=0

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Evaluation of Determinants
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon