The velocity of block B is x m/s. Then x is : (Pulley P1,P2 and P3 are movable. All other pulleys are fixed).
A
20
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B
30
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C
32
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D
25
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Solution
The correct option is A20 Consider a body X at the end of the pulley moving with 2m/s Now, making FBD of each body we have, vB⇒unknown vA=10↑ vC=4↓ vX=2↓ Now the total work done due to tension force should be zero ∴−TaB+4TaA−4TaC−2TaX=0 ∴−TvB+4TvA−4TvC−2TvX=0 ∴−aB+4(10)−4(4)−2(2)=0 ∴aB=20↓