Question

The zeroes of the polynomial $x^2-3x-m(m+3)$ are:

Answer 1

Factorise the given polynomial
We need to split the middle term minus three x as the sum of two terms, whose product is $-m(m+3)x^2$
$(x-(m+3\left)\right)(x+m)$
For finding zeroes of the polynomial, equate the polynomial to zero
$(x-(m+3\left)\right)(x+m)=0$
$(x-(m+3\left)\right)=0$ or $(x-(m+3\left)\right)(x+m)=0$
$x=m+3$ or $x=-m$.