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Question

There are two vessels A and B. Vessel A is containing 40 L of pure milk and vessel B is containing 22 L of pure water . From vessel A, 8 L of milk is taken out and poured into vessel B. Then, 6L of mixture (milk and water) is taken out from vessel B and poured into vessel A. What is the ratio of the quantity of pure milk in vessel A to the quantity of pure water in vessel B?

A
14 : 9
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B
21 : 11
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C
24:13
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D
14 : 5
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E
21 : 13
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Solution

The correct option is B 21 : 11

Initial quantity of milk in vessel A = 40 L
Initial quantity of water in vessel 8 = 22 L
Now, 8 L of milk is poured to vessel B.
Quantity of milk left in vessel,
A=40-8 =32 L
Quantity of milk in vessel B =8 L and quantity of water in vessel B =22 l
(Milk : water ) in vessel
B =8 : 22 =4 : 11
Now, 6 L of mixture (milk and water) is taken out from vessel B and poured into vessel A.
Quantity of milk in 6 L
=6×415=2×45=85
and quantity of water in 6 L
=6×1115=2×115=225
Now, quantity of milk in vessel A
=32+85=1685
and quantity of water in vessel B
=22225=885
Required ratio =1685:885
=168 : 88 = 21 : 11

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