wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Try simplifying these:

(i) (3x + 2y) − (x + y)

(ii) (3x + 2y) − (x − y)

(iii) (x + y) − (x − y)

(iv) (x − y) − (x + y)

(v) (4x − 3y) − (2x − 5x)

Open in App
Solution

(i)

(3x + 2y) (x + y)

= (3x + 2y x) y {x − (y + z) = (x − y) z for all numbers x, y, z}

= (3x x + 2y) y

= 2x + 2y y

= 2x + y

(ii)

(3x + 2y) (x y)

= 3x + 2y x + y {x − (y z) = x − y + z for all numbers x, y, z}

= 3x x + 2y + y

= 2x + 3y

(iii)

(x + y) (x y)

= x + y x + y {x − (y z) = x − y + z for all numbers x, y, z}

= x x + y + y

= 2y

(iv)

(x y) (x + y)

= (x y x) y {x − (y + z) = (x − y) z for all numbers x, y, z}

= (x x y) y

= y y

= 2y

(v)

(4x 3y) (2x 5x)

= 4x 3y (3x)

= 4x 3y + 3x

= 4x + 3x 3y

= 7x 3y


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Laws of Exponents
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon