Step 1: Find the work function.
Formula used: ϕ0=hv−eV0
Given:
Wavelength of ultraviolet light,
λ=2271∘A
λ=2271×10−10m
Stopping potential of the metal, V0=1.3V
Planck's constant, h=6.6×10−34Js
Charge on an electron, e=1.6×10−19C
Wavelength of red light,
λR=6328∘A=6328×10−10m
If the work function of the metal is ϕ and the frequency of incident radiation is v,
Then Work function is given by: ϕ0=hv−eV0
ϕ0=hcλ−eV0
ϕ0=6.63×10−34×3×1082271×10−10−1.6×10−19×1.3
ϕ0≈8.75×10−19−2.08×10−19
ϕ0≈6.7×10−19J
ϕ in electron volt (eV)
=6.7×10−191.6×10−19eV
ϕ0=4.2 eV
Step 2 : Find the theshold frequency.
Formula used : ϕ0=hv0
Let v0 be the threshold frequency of the metal, then, we have,
ϕ0=hv0
v0=ϕ0h
v0=6.7×10−196.63×10−34
v0=1.01×1015Hz
Step 3: Find the frequency of red light.
Formula used: vR=cλR
Now frequency of red light
vR=cλR
vR=3×1086328×10−10
vR≈4.74×1014Hz
Since v0>vr, the photo - cell will not respond
howsoever high be the intensity of laser light.
Final Answer : ϕ0=4.2 eV
v0≈1×1015Hz
vR≈4.74×1014Hz