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Question

Under what conditions current passing through a resistance R can be increased by short-circuiting the battery of emf E2. The internal resistances of the two batteries are r1 and r2 respectively.

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Solution

From the given diagram, we observe that both cells are in series combination with same polarity. So,

Equivalent emf, Eeq=E1+E2

And equivalent resistance of the circuit will be

Req=R+r1+r2

The current through the circuit before the battery of emf E2 is short-circuited is,

I1=EeqReq=E1+E2R+r1+r2

After short-circuiting the battery of emf E2, current through resistance R would be,

I2=E1R+r1

Now, I2>I1

E1R+r1>E1+E2R+r1+r2

E1r2>E2(R+r1)

Hence, the correct answer is option (b).

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