Under what conditions current passing through a resistance R can be increased by short-circuiting the battery of emf E2. The internal resistances of the two batteries are r1 and r2 respectively.
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Solution
From the given diagram, we observe that both cells are in series combination with same polarity. So,
Equivalent emf, Eeq=E1+E2
And equivalent resistance of the circuit will be
Req=R+r1+r2
The current through the circuit before the battery of emf E2 is short-circuited is,
I1=EeqReq=E1+E2R+r1+r2
After short-circuiting the battery of emf E2, current through resistance R would be,