We know that (a + b + c)2 = a2 + b2 + c2 + 2ab + 2bc + 2ac.
Comparing (4l – 2m – 3n)2 with (a + b + c)2 , we get:
a = 4l, b = –2m and c = –3n
Substituting these in the above formula:
(4l – 2m – 3n)2 = (4l)2 + (–2m)2 + (–3n)2 + 2 × (4l) × (–2m) +2× (–2m)×(–3n) + 2 × (–3n) × (4l)
= 16l2 + 4m2 + 9n2 – 16lm + 12mn – 24ln