Using an identity expand :
$(2 y + 5) (2 y + 5)$

$4 y^{2} + 10 y + 25$

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$4 y^{2} + 20 y + 25$

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$4 y^{2} + 20 y + 15$

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$y^{2} + 20 y + 25$

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Solution

The correct option is B
$4 y^{2} + 20 y + 25$

We know that,
$(a + b) \times (a + b) = (a + b)^{2}$

Using the identity
$(a + b)^{2} = a^{2} + 2 a b + b^{2}$ ,

$(2 y + 5) (2 y + 5) = (2 y + 5)^{2}$
$= (2 y)^{2} + 2 (2 y) (5) + 5^{2}$
$= 4 y^{2} + 20 y + 25$

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