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Question

Using divisibility tests, determine which of the following numbers are divisible by $ 2$; by $ 3$; by$ 4$; by $ 5$; by$ 6$; by $ 8$; by $ 9$; by $ 10$; by $ 11$ (say, yes or no):


\begin{tabular}{|l|l|l|l|l|l|l|l|l|l|} \hline \multicolumn{1}{|c|}{} & \multicolumn{6}{c|}{ Divisible By } \\ \hline Numbers & 2 & 3 & 4 & 5 & 6 & 8 & 9 & 10 & 11 \\ \hline 128 & Yes & No & No & Yes & No & No & Yes & No & No \\ \hline 990 & \( -- \) & \( -- \) & \( -- \) & \( -- \) & \( -- \) & \( -- \) & \( -- \) & \( -- \) & \( -- \) \\ \hline 1586 & \( -- \) & \( -- \) & \( -- \) & \( -- \) & \( -- \) & \( -- \) & \( -- \) & \( -- \) & \( -- \) \\ \hline 275 & \( -- \) & \( -- \) & \( -- \) & \( -- \) & \( -- \) & \( -- \) & \( -- \) & \( -- \) & \( -- \) \\ \hline 6686 & \( -- \) & \( -- \) & \( -- \) & \( -- \) & \( -- \) & \( -- \) & \( -- \) & \( -- \) & \( -- \) \\ \hline 639210 & \( -- \) & \( -- \) & \( -- \) & \( -- \) & \( -- \) & \( -- \) & \( -- \) & \( -- \) & \( -- \) \\ \hline 429714 & \( -- \) & \( -- \) & \( -- \) & \( -- \) & \( -- \) & \( -- \) & \( -- \) & \( -- \) \\ \hline 2856 & \( -- \) & \( -- \) & \( -- \) & \( -- \) & \( -- \) & \( -- \) & \( -- \) & \( -- \) \\ \hline 3060 & \( -589 \) & \( -- \) & \( -- \) & \( -- \) & \( -- \) & \( -- \) \\ \hline \end{tabular}

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Solution

Rules for divisibility :

  • Divisibility Rule of 2

If a number is even or a number whose last digit is an even number i.e. 2,4,6,8 including 0, it is always completely divisible by 2.

  • Divisibility Rules for 3

Divisibility rule for 3 states that a number is completely divisible by 3 if the sum of its digits is divisible by 3.

  • Divisibility Rule of 4

If the last two digits of a number are divisible by 4, then that number is a multiple of 4 and is divisible by 4 completely.

  • Divisibility Rule of 5

Numbers, which last with digits, 0 or 5 are always divisible by 5.

  • Divisibility Rule of 6

Numbers which are divisible by both 2 and 3 are divisible by 6 That is, if the last digit of the given number is even and the sum of its digits is a multiple of 3, then the given number is also a multiple of 6.

  • Divisibility Rules for 7

The rule for divisibility by 7 is a bit complicated which can be understood by the steps given below:

  • Divisibility Rule of 8

If the last three digits of a number are divisible by 8, then the number is completely divisible by 8.

  • Divisibility Rule of 9

The rule for divisibility by 9 is similar to divisibility rule for 3. That is, if the sum of digits of the number is divisible by 9, then the number itself is divisible by 9.

  • Divisibility Rule of 10

Divisibility rule for 10 states that any number whose last digit is 0, is divisible by 10.

  • Divisibility Rules for 11

If the difference of the sum of alternative digits of a number is divisible by 11, then that number is divisible by 11 completely.

Hence, the required complete table is:


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