Using identities, evaluate 297x303.
To Evaluate : 297x303
297 can be written as (300–3) and 303 can be written as (300+3)
297x303=(300–3)×(300+3)
Using the identity
(a+b)(a–b)=a2–b2
(300–3)×(300+3)=(300)2–(3)2(300–3)×(300+3)=3002–32(300–3)×(300+3)=90000–9(300–3)×(300+3)=89991
∴297x303=89991
Hence the result is 89991
Using identities, evaluate 297 × 303 = ___