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Question

Using identities, evaluate 297x303.


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Solution

To Evaluate : 297x303

297 can be written as (3003) and 303 can be written as (300+3)

297x303=(3003)×(300+3)

Using the identity

(a+b)(ab)=a2b2

(3003)×(300+3)=(300)2(3)2(3003)×(300+3)=300232(3003)×(300+3)=900009(3003)×(300+3)=89991

297x303=89991

Hence the result is 89991


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