Question

Using the prime factor method, find the H.C.F. of
(iv) $48,84\text{and}88$

Answer 1

(iv) Factor of a number: The number by which the given number can be divided completely.
Prime factors of $48=2\times 2\times 2\times 2\times 3$
Prime factors of $84=2\times 2\times 3\times 7$
Prime factors of $88=2\times 2\times 2\times 11$
$\therefore$ Common prime factors $=2\times 2$
Hence, H.C.F. of $48,84\text{and}88=2\times 2=4$