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Motion Under Gravity

v ∧ 2 = u ∧+2...

Question

v^2=u^+2as when u=0 , v^2=2as but when we consider v=u+at , v=at since u=0 . wkt t=s/v which implies v=a(s/v) we get v^2=as how is this possible ?

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Solution

That is a very good question.I am glad you asked it.
Now what exactly happend is that, you forgot a simple and basic fact.
In the second case, you took
time = s/v
You cant simply apply this in all the cases.
We are talking about uniformly accelarated motion. ie there is an accelaration value coming, that you just skipped.

The equation time = s/v can be applied only for uniform velocity.

Hope you get it.

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