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Value of sin ...

Question

Value of $s i n 37 ° . c o s 53 °$ is

A

9/25

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B

12/25

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C

16/25

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D

3/5

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Solution

The correct option is A 9/25
$s i n 37 ° . c o s 53 ° = s i n 37. c o s (90 - 37) = s i n^{2} 37 = 9 / 25$

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Similar questions

Q. Without using trigonometric tables, prove that:

(i) sin53° cos37° + cos53° sin37° = 1
(ii) cos54° cos36° − sin54° sin36° = 0
(iii) sec70° sin20° + cos20° cosec70° = 2
(iv) sin35° sin55° − cos35° cos55° = 0
(v) (sin72° + cos18°)(sin72° − cos18°) = 0
(vi) tan48° tan23° tan42° tan67° = 1

Q. If the system is in equilibrium (

c o s 53

^{0}

3 / 5

), then the value of

^{'} P^{'}

Q. Without using trigonometric tables, prove that:
(i) sin53° cos37° + cos53° sin37° = 1
(ii) cos54° cos36° − sin54° sin36° = 0
(iii) sec70° sin20° + cos20° cosec70° = 2
(iv) tan 15° tan 60° tan 75° =

\sqrt{3}

(v) tan48° tan23° tan42° tan67° tan 45° = 1
(vi) (sin72° + cos18°)(sin72° − cos18°) = 0
(vii) cosec 39° cos 51° + tan 21° cot 69° – sec²21° = 0

\frac{\sqrt{3} cos 23^{\circ} - sin 23^{\circ}}{2} = cos 53^{\circ}

Q. How to calculate

sin 37

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