Let the initial point is P(2,−2) and vectors −−→PA=2^i+4^j,−−→PB=3^i+6^j,−−→PC=(λ−2)^i+5^j
then for terminal point, −−→PA=−−→OA−−−→OP
⇒−−→OA=−−→PA+−−→OP=4^i+2^j
similarly, −−→OB=−−→PB+−−→OP=5^i+4^j and
−−→OC=−−→PC+−−→OP=λ^i+3^j
for collinear points of A,B,C slope of AB=slope of AC
⇒4−25−4=3−2λ−4⇒λ−4=12∴2λ=9