Q). Verify that x3 + y3 = (x+y) ( x2 - xy + y2)
1). R.H.S => (x+y) ( x2 - xy + y2)
=> x3 - x2y + xy2 + x2y - xy2 + y3 {On multiplying x3 + y3 with (x+y) ( x2 - xy + y2)}
=> [x3 + y3] + ( -x2y + x2y) + ( xy2 - xy2)
=> x3 + y3
Since R.H.S = L.H.S,
That is x3 + y3 = x3 + y3
Hence, verified that x3 + y3 = (x+y) ( x2 - xy + y2)
OR
2). L.H.S => Using identities.. (a3 + b3) = (a+b)(a2 - ab +b2)
=> (x+y) [(x)2 - ( x * y ) + (y)2]
=> (x+y) ( x2 - xy + y2)
Since, L.H.S = R.H.S,
that is (x+y) ( x2 - xy + y2) = (x+y) ( x2 - xy + y2)
Hence verified that x3 + y3 = (x+y) ( x2 - xy + y2)
Although, for verifying the first step is mostly used !