Question 4(vi) Simplify: (ab+bc)2−2ab2c
(ab+bc)2−2ab2c =(ab)2+2×ab×bc+(bc)2−2ab2c [Using identity (a+b)2=a2+2ab+b2]a2b2+2ab2c+b2c2−2ab2ca2b2+b2c2
Simplify.
(i) (a2 − b2)2 (ii) (2x +5)2 − (2x − 5)2
(iii) (7m − 8n)2 + (7m + 8n)2 (iv) (4m + 5n)2 + (5m + 4n)2
(v) (2.5p − 1.5q)2 − (1.5p − 2.5q)2
(vi) (ab + bc)2 − 2ab2c (vii) (m2 − n2m)2 + 2m3n2