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Question

Question 4(vi)
Simplify:
(ab+bc)22ab2c

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Solution

(ab+bc)22ab2c
=(ab)2+2×ab×bc+(bc)22ab2c
[Using identity (a+b)2=a2+2ab+b2]a2b2+2ab2c+b2c22ab2ca2b2+b2c2


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