Factorise
$(x^{2} - 2 x y + y^{2}) - z^{2}$

Open in App

Solution

We have $(x^{2} - 2 x y + y^{2}) - z^{2}$
$= [(x)^{2} - 2 \times x \times y + (y)^{2}] - z^{2}$
$= (x - y)^{2} - (z)^{2} [∵ (a - b)^{2} = a^{2} - 2 a b + b^{2}]$
$= (x - y - z) (x - y + z) [∵ a^{2} - b^{2} = (a - b) (a + b)]$

Suggest Corrections

Similar questions

\frac{x^{2} + y^{2} - z^{2} + 2 x y}{x^{2} - y^{2} - z^{2} - 2 y z} .

(x^{2} - 2 x y + y^{2}) - z^{2}

z^{2} - (x^{2} - 2 x y + y^{2})

(x^{2} - 2 x y + y^{2}) - z^{2}

(x^{2} - 2 x y + y^{2}) - z^{2}

Join BYJU'S Learning Program

Explore more

Join BYJU'S Learning Program