Subtract

$- 3 p^{2} + 3 p q + 3 p x$ from $3 p (- p - a - r)$

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Solution

We have, to subtract $- 3 p^{2} + 3 p q + 3 p x$ from $3 p (- p - a - r)$
The required difference is given by
$3 p (- p - a - r) - (- 3 p^{2} + 3 p q + 3 p x)$
$= - 3 p^{2} - 3 a p - 3 p r + 3 p^{2} - 3 p q - 3 p x$
$= (- 3 p^{2} + 3 p^{2}) - 3 a p - 3 p r - 3 p q - 3 p x$ [grouping like terms]
$= - 3 a p - 3 p r - 3 p q - 3 p x$

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