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B
8√2r3
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C
16√2r3
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D
24√3r3
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Solution
The correct option is A24√2r3 From the figure: tan 300=a2×y or y=a×√32×1=√32a Area of hexagonal surface =6[1a2×√3a2]=6√3a24 Volume of hexagon = Area of base × Height =6√34×a2×2√23a =6√34×(2r)2×2√23(2r)=24√2r3