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Question

m(NH4OH) is equal to

A
m(NH4OH)+m(NH4Cl)m(HCl)
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B
m(NH4Cl)+m(NaOH)m(NaCl)
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C
m(NH4Cl)+m(NaCl)m(NaOH)
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D
m(NaOH)+m(NaCl)m(NH4Cl)
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Solution

The correct option is B m(NH4Cl)+m(NaOH)m(NaCl)
According to kohlrausch’s law
the value of equivalent conductance at infinite dilution for any electrolyte is the sum of contribution of its constituent ions.
So
m(NH4OH)=mNH+4+mOH...(1)m(NH4Cl)=mNH+4+mCl...(2)m(NaOH)=mNH+4+mOH...(3)m(Nacl)=mN++mCl...(4)
Eq (1) = Eq(2) + Eq(3) – Eq(4)
Therefore ,
m(NH4Cl)+m(NaOH)m(NaCl)

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