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Question

What are the minimum number of carbon atoms required for alkanes, alkenes and for alkynes to exhibit positional isomerism respectively?

A
2, 2, 2
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B
2, 4, 6
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C
6, 4, 2
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D
6, 4, 4
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Solution

The correct option is D 6, 4, 4
In an alkane chain, at least 6 C atoms are required. In an alkyne chain, at least 4 C atoms are required. In an alkene chain, at least 4 C atoms are required. So, the correct answer will be option (d).


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