Question

What are the molecular shapes of ${\mathrm{SF}}_4$, ${\mathrm{CF}}_4$, and ${\mathrm{XeF}}_4$?

• A. same with $1,1,\mathrm{and}1$ lone pair of electrons respectively
• B. same with $2,0,\mathrm{and}1$ lone pair of electrons respectively
• C. different with $1,0,\mathrm{and}2$ lone pair of electrons respectively
• D. different with $0,1,\mathrm{and}2$ lone pair of electrons respectively

Answer 1

The correct option is C

different with $1,0,\mathrm{and}2$ lone pair of electrons respectively

Explanation for correct option:

(c ) different with $1,0,\mathrm{and}2$ lone pairs of electrons respectively

• ${\mathrm{SF}}_4$ – ${\mathrm{sp}}^3\mathrm{d}$, trigonal bipyramidal with one lone pair at the equatorial position
• 
  ${\mathrm{CF}}_4$ – ${\mathrm{sp}}^3$ tetrahedral molecule with no lone pair.
  
• 
  ${\mathrm{XeF}}_4$ – ${\mathrm{sp}}^3{\mathrm{d}}^2$, square planar, two lone pairs.
• 
• So, option (C) is correct.

Explanation for incorrect options :

The molecular shapes of ${\mathrm{SF}}_4$, ${\mathrm{CF}}_4$, and ${\mathrm{XeF}}_4$ is different with $1,0,\mathrm{and}2$ lone pair of electrons respectively.Hence, options (A), (B),and (D) are incorrect.

Therefore the correct option is (C).