What is C35?
Determine C35.
we know,Crn=n!r!(n-r)!
To calculate, put n=5,r=3 in the above formula:
Crn=n!r!(n-r)!⇒C35=5!3!(5-3)!⇒C35=5!3!(5-3)!⇒C35=5!3!(2)!⇒C35=5×4×3!3!×2×1⇒C35=5×42×1⇒C35=5×2⇒C35=10
Hence, the required value is C35=10