The correct option is D 4.82 g
Given:
Volume of the solution = 14.86 mL
Consider the mass of the solute to be x g.
Since, 100 mL of the solution contains 32.44 g of KI,
14.86 mL of solution will contain,
=32.44100 g mL−1×14.86 mL=4.82 g
14.86 mL KI solution contains 4.82 g of KI.