Question

What is the measure of each interior angle of an $18$sided polygon?

Answer 1

Find the required measure of each interior angle:

For a $\text{'}\mathrm{n}\text{'}$sided polygon, measure of each interior angle is $\frac{\left(\mathrm{n}-2\right)180°}{\mathrm{n}}$

Given that $\mathrm{n}=18$, measure of each interior angle is $=\frac{\left(18-2\right)180°}{18}$

$=\frac{\left(16\right){\cancel{180°}}^{10}}{\cancel{18}}$

$=160°$

Hence, the measure of each interior angle of an $18$sided polygon is $160°$.