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Physical Properties (Group 1)

what is the m...

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what is the molar solubility of AgCl(s) in 0.1M NH3 (aq)?Ksp(AgCl)=1.810^-10 ,Kf[Ag(NH3)2]^+=1.610^7.

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Similar questions

Q. The concentration of

{N H}_{3}

solution whose one litre can dissolve

0.10

A g C l

K_{s p}

A g C l

K_{f}

A g {({N H}_{3})}_{2}^{+}

10^{- 10} M^{2}

1.6 \times 10^{7} M^{- 2}

Q. One liter of

N H_{3}

solution dissolves 0.10 mole of AgCl. Its concentration is:

(K_{s p}

K_{f}

[A g (N H_{3})_{2}]^{+}

10^{- 10} and 1.6 \times 10^{7}

Q. Calculate the solubility of AgCl in 0.2 M -

N H_{3}

solution.
Given : Ksp of AgCl = 2 x 10, Kf of

A g (N H_{3}) 2^{+}

10^{6}

Q. What is the concentration of

A g^{+}

0.01 M A g N O_{3}

1.0 M N H_{3}

A g C l

precipitate from a solution that is

0.01 M A g N O_{3}

0.01 M N a C l

1 M N H_{3}

?
Given : Formation constant,

K_{f} o f [A g (N H_{3})_{2}]^{+} = 1.70 \times 10^{7} a n d K_{s p} A g C l = 1.8 \times 10^{- 10}

Q. What is the solubility of

A g C l

0.20 M

{N H}_{3}

K_{s p} (A g C l) = 1.7 \times 10^{- 10}

M^{2}

K_{1} = [A g {({N H}_{3})}^{+}] / [{A g}^{+}] [{N H}_{3}] = 2.33 \times 10^{3} M^{- 1}

K_{2} = [A g {({N H}_{3})}_{2}^{+}] / [A g {({N H}_{3})}^{+}] [{N H}_{3}] = 7.14 \times 10^{3} M^{- 1}

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