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Question

What is the proof that a^0=1?

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Solution

a^0 = a^(1 - 1)

a^0 = [a^1] × [a^(-1)]

a^0 = a × (1/a) [since a^1 = a & a^(-1) = 1/a]

a^0 = a / a

a^0 = 1

Hence proved!


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