The correct option is C
Explanation of the correct answer:
- The cross between F1 heterozygous parent and homozygous parent for two characters is called dihybrid test cross.
- We can assume that the genotype of one parent is RrYy, if R is the gene for seed shape and Y is the gene for seed colour.
- Then the genotype of the other parent involved in the dihybrid test cross will be rryy, i.e., recessive for all traits.
- Then the test cross can be represented as follows:
-
- Therefore, total number of genotypes and phenotypes are 4 + 4 = 8.
Explanation of the incorrect answers:
Option A:
- The number of genotypes in dihybrid test cross are 4.
- The number of phenotypes in dihybrid test cross are also 4.
- Therefore, total number of genotypes and phenotypes are 4 + 4 = 8.
Option B:
- The number of genotypes in dihybrid test cross are 4.
- The number of phenotypes in dihybrid test cross are also 4.
- Therefore, total number of genotypes and phenotypes are 4 + 4 = 8.
Option D:
- The number of genotypes in dihybrid test cross are 4.
- The number of phenotypes in dihybrid test cross are also 4.
- Therefore, total number of genotypes and phenotypes are 4 + 4 = 8.
Final answer: The total number of genotypes and phenotypes in a dihybrid test cross are 8.