The correct option is C 3
Given equation: x + 2 = 5
now using trial and error method,
case 1:
Putting x = 1 in the equation,
we get LHS = 1 + 2 = 3 and RHS = 5
Hence, LHS is not equal to RHS.
case 2:
Putting x = 2 in the equation,
we get LHS = 2 + 2 = 4 and RHS = 5
Hence, LHS is not equal to RHS.
case 3:
Putting x = 3 in the equation,
we get LHS = 3 + 2 = 5 and RHS = 5
Hence, LHS is equal to RHS.
∴ x = 3 is the solution for given equation.