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Question

The kinetic energy of an object of mass, m moving with a velocity of 5ms-1 is 25J, What will be its kinetic energy when its velocity is doubled? What will be its kinetic energy when its velocity is increased three times?


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Solution

Step 1: Given data

The kinetic energy of an object (K.E) = 25J

The velocity of the object (V) = 5ms-1

Mass of the object = m

Step 2: Formula used

K.E=12mv2

For the mass of the object

K.E=12mv225=12×m×5250=25mm=2kg

Step 3: Calculation

Case 1:

When velocity is doubled, then

v=10ms-1m=2kg

So

K.E=12mv2K.E=12×2×102K.E=100J

So its kinetic energy is 100J when its velocity is doubled.

Case 2:

When its velocity is increased three times, then

v=15ms-1m=2kg

So

K.E=12mv2K.E=12×2×152K.E=225J

So its kinetic energy is 225J when its velocity is increased three times.


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