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Question

When 100g of a liquid A at 100oC is added to 50g of a liquid B at temperature 75oC, the temperature of the mixture becomes 90oC. The temperature of the mixture, if 100g of liquid A at 100oC is added to 50g of liquid B at 50oC, will be?

A
80oC
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B
60oC
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C
70oC
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D
85oC
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Solution

The correct option is A 80oC
100×SA×[10090]=50×SB×(9075)
2SA=1.5SB
SA=34SB
Now, 100×SA×[100T]=50×SB(T=50)
2×(34)(100T)=(T50)
3003T=2T100
400=5T
T=80.

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