When 100g of a liquid A at 100oC is added to 50g of a liquid B at temperature 75oC, the temperature of the mixture becomes 90oC. The temperature of the mixture, if 100g of liquid A at 100oC is added to 50g of liquid B at 50oC, will be?
A
80oC
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B
60oC
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C
70oC
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D
85oC
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Solution
The correct option is A80oC 100×SA×[100−90]=50×SB×(90−75) 2SA=1.5SB SA=34SB Now, 100×SA×[100−T]=50×SB(T=50) 2×(34)(100−T)=(T−50) 300−3T=2T−100 400=5T T=80.