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Normality

When 20 ml ...

Question

When $20$ ml of a mixture of $O_{2}$ and $O_{3}$ is heated, the volume becomes $29 m l$ and disappears in alkaline pyragallol solution. What is the volume percent of $O_{2}$ in the original mixture?

A

90 %

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B

77.5 %

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C

18 %

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D

2 %

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Solution

The correct option is B $77.5 %$
On heating $O_{3}$ converts into $O_{2}$ and the volume increases. Let's say volume of $O_{3}$ be $v$ and then volume of $O_{2} = 20 - v$
$2 O_{3} ⟶ 3 O_{2}$
$2 v$ $3 v$
Since they are disappeared in alkaline pyragallol solution.
$20 - v + 3 v = 29 \Rightarrow v = 4.5 m l$
$∴$ Volume of $O_{2}$ will be $20 - 4.5 = 15.5 m l$
$∴$ Volume percent of $O_{2}$ in the mixture= $\frac{15.5}{20} = 77.5$ %

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