Question

When $a=3$, $b=0$, and $c=-2$ , find the value of :

$a^3+b^3+c^3-3abc$

Answer 1

We have $a^3+b^3+c^3-3abc$

Substituting $a=3$, $b=0$, and $c=-2$ in given expression we get

$$\begin{gathered} a^3+b^3+c^3-3abc=3^3+0^3+\left(-2^3\right)-3\times 3\times 0\times \left(-2\right) \\ =27+0-8-0 \\ =27-8 \\ =19 \end{gathered}$$

Hence , the value of $a^3+b^3+c^3-3abc$ is $19$