Question

When simplified $\left(256\right){}^{-\left(4^{-3/2}\right)}$ is

(a) 8

(b) $\frac{1}{8}$

(c) 2

(d) $\frac{1}{2}$

Answer 1

Simplify

${\left(256\right)}^{{-}^{\left(4^{-\raisebox{1ex}{$3$}\!\left/ \!\raisebox{-1ex}{$2$}\right.}\right)}}={\left(256\right)}^{-{\left(2\right)}^{\left(-3\right)}}$

Hence the correct choice is .