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Question

Which compound shows cis-trans isomerism?

A
1-butene
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B
2-propene
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C
2-butene
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D
benzene
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Solution

The correct option is C 2-butene
Conditions for geometrical isomers:
1) Free rotation must be restricted.
2) Both the terminals must be attached with different groups.
3) Terminals must not be in perpendicular planes.

1-butene has two same groups attached to the one of the terminal carbon of the double bond so it can't show geometrical isomerism

2-propene has two same groups attached to the one of the terminal carbon of the double bond so it can't show geometrical isomerism

2-butene has two different groups (H) and (CH3) attached to the terminal carbon of the both double bond so it can show geometrical isomerism.

d can't show geometrical isomerism
hence correct option is c.

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