The correct option is C 2-butene
Conditions for geometrical isomers:
1) Free rotation must be restricted.
2) Both the terminals must be attached with different groups.
3) Terminals must not be in perpendicular planes.
1-butene has two same groups attached to the one of the terminal carbon of the double bond so it can't show geometrical isomerism
2-propene has two same groups attached to the one of the terminal carbon of the double bond so it can't show geometrical isomerism
2-butene has two different groups (H) and (CH3) attached to the terminal carbon of the both double bond so it can show geometrical isomerism.
d can't show geometrical isomerism
hence correct option is c.