Which expression is a factor of $m^{4} - 16$ ?

m + 5

No worries! We‘ve got your back. Try BYJU‘S free classes today!

m - 4

No worries! We‘ve got your back. Try BYJU‘S free classes today!

m^{2} + 2

No worries! We‘ve got your back. Try BYJU‘S free classes today!

m - 2

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D $m - 2$
$m^{4} - 16 = (m^{2})^{2} - 4^{2}$
$= (m^{2} - 4) (m^{2} + 4)$
$= (m + 2) (m - 2) (m^{2} + 4)$
Factors of $m^{4} - 16$ are $(m + 2) (m - 2) (m^{2} + 4)$
Answer : D

Suggest Corrections

Similar questions

n \sum m = 1 t a n^{- 1} (\frac{2 m}{m^{4} + m^{2} + 2}) =

n \sum m = 1 {tan}^{- 1} (\frac{2 m}{m^{4} + m^{2} + 2})

Factorize: $m^{4} - 256.$

If $m - \frac{1}{m} = 5,$ find :

(i) $m^{2} + \frac{1}{m^{2}}$

(ii) $m^{4} + \frac{1}{m^{4}}$

(iii) $m^{2} - \frac{1}{m^{2}}$

n \sum m = 1 {tan}^{- 1} (\frac{2 m}{m^{4} + m^{2} + 2})

Join BYJU'S Learning Program