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Question

Which of the following hydrocarbons can decolorize the alkaline potassium permanganate solution?


A

C2H6

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B

C3H8

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C

C5H12

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D

C3H6

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Solution

The correct option is D

C3H6


The explanation for correct option

(D):

  • An unsaturated organic compound decolorizes the pink color of potassium permanganate when treated with Baeyer's reagent, an aqueous solution of alkaline Potassium Permanganate KMnO4.
  • The purple color of alkaline KMnO4 solution changes to brown due to the formation of MnO2.
  • Cold dilute neutral or alkaline KMnO4 solution quickly oxidizes alkenes to yield vicinal or 1,2-glycol.
  • C3H6 is an unsaturated hydrocarbon (an alkene) as it satisfies the general formula of alkene CnH2n.
  • C3H6 (Propene) reacts with alkaline KMnO4 solution and decolorizes it.
  • The reaction is as follows:

Explanation for the incorrect options

(A) C2H6:

  • The general formula of alkane is CnH2n+2. C2H6 (Ethane) is an alkane.
  • Due to the presence of saturation, C2H6 do not decolorize the alkaline KMnO4 solution.

(B) C3H8:

  • The general formula of alkane is CnH2n+2. C3H8 (Propane) is an alkane.
  • Due to the presence of saturation, C3H8 do not decolorize the alkaline KMnO4 solution.

(C) C5H12:

  • The general formula of alkane is CnH2n+2. C5H12 (Pentane) is an alkane.
  • Due to the presence of saturation, C5H12 do not decolorize the alkaline KMnO4 solution.

Therefore, the correct option is (D). C3H6 can decolorize the alkaline Potassium Permanganate solution.


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