Which of the following is correct regarding the structure intermediate formed during the following reaction?
$C_{6} H_{6} + C o n c . H N O_{3} + C o n c . H_{2} S O_{4} 323 - 333 K - ----- \to C_{6} H_{5} N O_{2} + H_{2} O$

All the carbons are

s p^{2}

hybridised.

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Intermediate is non aromatic in nature

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All carbons are

s p^{3}

hybridised

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None of the above

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Solution

The correct option is B Intermediate is non aromatic in nature
Nitration of benzene :
$C_{6} H_{6} + C o n c . H N O_{3} + C o n c . H_{2} S O_{4} 323 - 333 K - ----- \to C_{6} H_{5} N O_{2} + H_{2} O$

It has one carbon $s p^{3}$ hybridised rest are $s p^{2}$ hybridised. Intermediate is partially resonance stabilized. So, intermediate formed is non aromatic in nature.

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