Question

Which of the following is expected to be optically active?

• A. $(C{H}_3{)}_{4}C$
• B. $C_5{H}_{5}CH\left(C{H}_3\right)C_3{H}_7$
• C. $\left(C_2{H}_5\right)CH\left(C{H}_3\right)C_2{H}_5$
• D. $C{H}_{3}CH=CHC{H}_3$

Answer 1

The correct option is B $C_5{H}_{5}CH\left(C{H}_3\right)C_3{H}_7$

Compounds which can rotate the plane of plane polarised light is known as optically active compounds. In optically active compounds, plane of symmetry and centre of symmetry are absent.

As all the four substituents attached are different. So it is chiral and also here plane of symmetry and centre of symmetry are absent. Hence, optical active.