Question

Which of the following is the correct order of melting points of group $16$ elements?

• A. $O<S<Se<Te<Po$
• B. $O<Se<S<Te<Po$
• C. $O<S<Se<Te>Po$
• D. $O<S<Se>Te<Po$

Answer 1

The correct option is C $O<S<Se<Te>Po$

$\begin{array}{c}\text{As we go down the group the melting point increases for group}16\text{as metallic character increases}\\ \text{But Te has highest melting point due to less}\\ \text{sheielding of its electrons and more packed solid}\\ \text{structure.}\end{array}$

$\text{So, option C)}O<S<\text{Se}<\text{Te}>\text{Po is correct}$