Which value of $y$ makes the equation $3 y + 8 = 7 y + 11$ true?

$- 4.75$

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$- 0.75$

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$0.75$

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$4.75$

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Solution

The correct option is B
$- 0.75$

Solve for $y$ :
$3 y + 8 = 7 y + 11$
Transposing variables to LHS and constants to RHS
$3 y - 7 y = 11 - 8 - 4 y = 3$
Dividing both sides by $- 4$ we get,
$y = \frac{- 3}{4}$
$y = - 0.75$

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Which value of y makes the equation 3y+8=7y+11 true?

The correct option is B -0.75Solve for y:3y+8=7y+11Transposing variables to LHS and constants to RHS3y-7y=11-8-4y=3 Dividing both sides by -4 we get,y=-34y=-0.75

Which value of $y$ makes the equation $3 y + 8 = 7 y + 11$ true?

The correct option is B
$- 0.75$

Solve for $y$ :
$3 y + 8 = 7 y + 11$
Transposing variables to LHS and constants to RHS
$3 y - 7 y = 11 - 8 - 4 y = 3$
Dividing both sides by $- 4$ we get,
$y = \frac{- 3}{4}$
$y = - 0.75$