Why ${C H}_{4}$ can not adopt square planar geometry?

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Solution

In $C H_{4}$ molecule, carbon is $s p^{3}$ Hybridized, so it is tetrahedral in shape.
For square planar, $d s p^{2}$ Hybridisation is required which is not possible in Carbon due to the absence of d - orbitals.
Also, we know, according to VSEPR theory, four bonded electron pairs around carbon atom arranged themselves in regular tetrahedral geometry, which bond angle is $109 ° 28^{'}$ while in square planar structure, the bond angle $90 °$ .
Therefore $C H_{4}$ can't be square planar. Hence, $C H_{4}$ is tetrahedral in shape.

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Why CH4 can not adopt square planar geometry?

Why ${C H}_{4}$ can not adopt square planar geometry?