Question

Write a Pythagorean triplet whose one member is 16

Answer 1

For any natural number m > 1, we have (2m) ² + (m2 – 1)²= (m2 + 1)² . So, 2m, m² – 1 and m² + 1 forms a Pythagorean triplet.

Let 2 m = 16,

m = 8

m² + 1 = 8² + 1 = 64 + 1 = 65

m²- 1 = 8 2 - 1 = 64 - 1 = 63

check:

16² + 63² = 256 + 3969 = 4225 = 65²

Hence, the triplet is 16, 63 & 65