Question

Write reactions of the final alkylation product of aniline with excess of methyl iodide in the presence of sodium carbonate solution.

Answer 1

Reaction of methyl iodide (excess) reacts with aniline

Aniline reacts with the excess of methyl iodide to form $\text{N,N,N- trimethylanilinium}$ iodide via nucleophilic substitution reaction which in the presence of sodium carbonate solution forms $\text{N, N, N− trimethyl}$ anilinium carbonate as a final product.

Involved reaction is shown below-