Consider given the equation,
4x−3y=0
Put, x=0
4×0−3y=0
−3y=0
y=0
Put again, x=1
4×1−3y=0
−3y=−4
y=43
Put again, x=2
4×2−3y=0
−3y=−8
y=83
The line 4x - 3y + 12 = 0 meets x-axis at A. Write the co-ordinates of A.
Determine the equation of the line through A and perpendicular to 4x - 3y + 12 = 0.