We have,
(2a+3b)3
Since,
(x+y)3=x3+y3+3xy(x+y)
Therefore,
(2a+3b)3=(2a)3+(3b)3+3×2a×3b(2a+3b)
(2a+3b)3=8a3+273+18ab(2a+3b)
(2a+3b)3=8a3+273+36a2b+54ab2
Hence, this is the answer.
Write the following cubes in expanded form: (2a−3b)3
Write the following cubes in expanded form: (i) (2x+1)3 (ii) (2a−3b)3