Write the general solution of tan2 2x=1.
tan2 2x=1⇒tan2 2x−1⇒(tan 2x−1)(tan 2x+1)=0⇒tan 2x=1 or tan 2x=−1⇒tan 2x=tan π4Or tan 2x=−tan(π4)=tan(π−π4)=tan (3π4)2x=xπ+ π4 Or 2x=xπ+3π4,x∈z⇒x=xπ2+π8 or x=xπ2+3π8⇒x=xπ2+π8,x∈z