Question

write the supplement of
80 degree 49' 25"

Answer 1

$$\begin{gathered} \mathrm{We}\mathrm{know}\mathrm{that}, \\ \mathrm{Two}\mathrm{angles}\mathrm{are}\mathrm{called}\mathrm{supplementary}\mathrm{if}\mathrm{they}\mathrm{add}\mathrm{up}\mathrm{to}{180}^{\mathrm{o}}. \\ \mathrm{For}\mathrm{e}.\mathrm{g}.{40}^{\mathrm{o}},{140}^{\mathrm{o}}\mathrm{these}\mathrm{are}\mathrm{a}\mathrm{pair}\mathrm{of}\mathrm{supplementary}\mathrm{angles} \\ \mathrm{So}\mathrm{to}\mathrm{determine}\mathrm{supplement}\mathrm{of}{80}^{\mathrm{o}}49\text{'}25",\mathrm{subtract}\mathrm{it}\mathrm{from}{180}^{\mathrm{o}}00\text{'}00" \\ \mathrm{We}\mathrm{can}\mathrm{represent}{180}^{\mathrm{o}}00\text{'}00"\mathrm{as} \\ {179}^{\mathrm{o}}59\text{'}60" \\ \mathrm{now}\mathrm{subtracting} \\ {179}^{\mathrm{o}}59\text{'}60"-{80}^{\mathrm{o}}49\text{'}25"={\mathbf{99}}^{\mathbf{o}}\mathbf{10}\mathbf{\text{'}}\mathbf{35}\mathbf{"} \\ \mathbf{Ans}\mathbf{}\mathbf{:}\mathbf{}{\mathbf{99}}^{\mathbf{o}}\mathbf{10}\mathbf{\text{'}}\mathbf{35}\mathbf{"} \end{gathered}$$